Probability Poker Hand Full House
We know that the probability of getting a full house is given by: P (Full house) = n (F)/n (S) n (S) = Number of elements in F = 52C5 = 2598960 In order to understand n (F), consider the following. Putting all of this together, we obtain the following ranking of poker hands: Poker Hand Number of Ways to Get This Probability of This Hand Royal Flush 4 0.000154% Straight Flush 36 0.00139% Four of a Kind 624 0.0240% Full House 3,744 0.144% Flush 5,108 0.197% Straight 10,200 0.392% Three of a Kind 54,912 2.11% Two Pairs 123,552 4.75% One Pair 1,098,240 42.3% Nothing 1,302,540 50.1% Wait, how did I compute the probability of getting “Nothing”?
- Probability Poker Hand Full House Images
- Probability Poker Hand Full House Or Flush Who Wins
- Probability Poker Hand Full House
- Probability Poker Hand Full House Rankings
A game of poker is played with an ordinary deck of 52 cards, and each player is dealt a hand of 5 cards chosen at random. What is the probability that a player will be dealt a full house, given that the first two cards they get are of the same denomination?
© BrainMass Inc. brainmass.com December 15, 2020, 8:06 pm ad1c9bdddfhttps://brainmass.com/math/probability/probability-poker-fullhouse-433206
Solution Preview
Given that we get two cards of the same denomination (let's say they are Xs), there are two possibilities,
1) The triple of the full house is that number (i.e. we have a triple X) and another pair (say a pair of Y), OR
2) The pair of the full house is the two cards we just got (i.e. a pair of Y and a triple X).
Let's consider case 2) first,
There are 50 cards left, and 2 of them are X (since we got 2 Xs already). Our third card ...
Solution Summary
The probability of obtaining a poker fullhouse is determined.
Andymath.com features free videos, notes, and practice problems with answers! Printable pages make math easy. Are you ready to be a mathmagician?